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 Topic: PHP and Mysql |
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| Author |
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fifimtwana
Joined: 24 Feb 2011
Posts: 22
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 Posted: Mon 11 Apr '11 14:01 Post subject: PHP and Mysql |
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Hey guys could you plese help me out... I'm new to PHP and have done research on the internet but have not been ble to find what im looking for..
My problem is that I want to be able to insert multiple records into a single table named "Attendance" using checkboxes. The array only inserts one record into the database,but doesnt insert the studentID in the ID column.
How do I Fix this problem, i've tried many solutions that I gt on the internet but they are just not helping..
Below is the code i used:
| Code: | <script language="javascript" src="calendar.js"></script>
<?php
//============================================PHP START================================================//
//===================================Connecting to DB START=========================================//
$mysqluser = 'root';
$mysqlpasswd = '689453';
$mysqlhost = 'localhost';
$mysqlDB = 'p10DB';
mysql_connect($mysqlhost,$mysqluser,$mysqlpasswd);
mysql_select_db($mysqlDB) or die( "Unable to select database");
//===================================Connecting to DB STOP=========================================//
//===================================SQL Query START=========================================//
$STATUS = 'ACTIVE';
$query55 = "select distinct Learnership, Level, YGroup from training_event where STATUS='$STATUS' order by Level";
$result55=mysql_query($query55);
$query2 = "select ID,Level from levels";
$result2=mysql_query($query2);
$num=mysql_numrows($result2);
$query3 = "select * from assessors";
$result3=mysql_query($query3);
$num=mysql_numrows($result3);
$LSHIP = $_GET[LSHIP];
$LVL = $_GET[LVL];
$GRP = $_GET[GRP];
$STATUS = "ACTIVE";
$query4 = "select ID,Name,Surname from students where Status='$STATUS' and LEARNERSHIP='$LSHIP' and LEVEL='$LVL' and YEARGROUP ='$GRP' order by Surname";
$result4=mysql_query($query4);
$num=mysql_numrows($result4);
?>
<table>
<TR>
<TD> <font size="2" face="bmwtyperegular">
Student Filter:
</TD>
<TD>
</TD>
</TR>
<?PHP
while($nt=mysql_fetch_array($result55))
{
?>
<TR>
<TD> <font size="2" face="bmwtyperegular">
</TD>
<TD>
<a href="indexp10_manage_students_book_student.php?LSHIP=<?PHP echo $nt[Learnership].'&LVL='.$nt[Level].'&GRP='.$nt[YGroup] ?>">
<font color="#808080" size="2" face="bmwtyperegular">
<?PHP echo $nt[Learnership].' '.$nt[Level].' '.$nt[YGroup];?>
</TD>
</TR>
<?PHP
}
?>
</table>
<table border=0 width=1000>
<tr>
<td>
<HR NOSHADE size="1" color="#eeeeee">
</td>
</tr>
</table>
<TABLE>
<font size="2" face="bmwtyperegular">
<FORM NAME ="ATT_REG" METHOD ="Get" ACTION = "">
<TR>
<TD>
<?PHP
$array_holder = 0;
?>
<TR>
<TD>
<?PHP
while($nt=mysql_fetch_array($result4))
{
$INPUTID[$array_holder] = $nt[ID];
?>
<TR>
<td align="right">
<input type="checkbox" name="<?PHP echo $array_holder ?>" value="<?PHP echo $nt[ID] ?>" checked>
</td>
<TD width="150"> <font size="2" face="bmwtyperegular">
<?PHP echo $nt[ID] ?>
</TD>
<TD width="150"> <font size="2" face="bmwtyperegular">
<?PHP echo $nt[Surname]; ?>
</TD>
<TD width="150"> <font size="2" face="bmwtyperegular">
<?PHP echo $nt[Name]; ?>
</TD>
</tr>
<?PHP
$array_holder++;
}
?>
</TD>
</TR>
<TR>
<TD> <font size="2" face="bmwtyperegular">
Leave Type:
</TD>
<TD>
<select name="Booking">
<option value="Offsite">Offsite Work</option>
<option value="Leave">Leave</option>
<option value="Sick">Sick Leave</option>
<option value="NO_SPEC">Change Time</option>
</select>
</TD>
</TR>
<TR>
<TD> <font size="2" face="bmwtyperegular">
Leave Date:
</td>
<TD>
<?PHP
require_once('classes/tc_calendar.php');
//instantiate class and set properties
$myDate = date("d/m/Y");
$myDateY = date("Y");
$myDateM = date("m");
$myDateD = date("d");
$myCalendar = new tc_calendar("date1", true);
$myCalendar->setIcon("iconCalendar.gif");
$myCalendar->setDate($myDateD, $myDateM, $myDateY);
$myCalendar->writeScript();
$theDate = isset($_REQUEST["date1"]) ? $_REQUEST["date1"] : "";
?>
<TD>
</TD>
</TR>
<TR>
<TD> <font size="2" face="bmwtyperegular">
Assessor ID:
</TD>
<TD>
<select name="AID">
<?PHP
while($nt=mysql_fetch_array($result3))
echo "<option value=$nt[ID]>$nt[Name] $nt[Surname]</option>";
echo "</select>";
?>
</TD>
</TR>
<TR>
<TD> <font size="2" face="bmwtyperegular">
PIN Code:
</TD>
<TD>
<input type="password" name="PIN" value="" size ="4">
</TD>
</table>
<input type="submit" name="SUB1" value="Book Learner">
</P>
</FORM>
<?PHP
$ID = $_GET['ID'];
$Booking = $_GET['Booking'];
$Date = $_GET['Date'];
$Date = $theDate[8].$theDate[9].'/'.$theDate[5].$theDate[6].'/'.$theDate[0].$theDate[1].$theDate[2].$theDate[3];
$AID = $_GET['AID'];
$PIN = $_GET['PIN'];
$Time = "06:59:59am";
$query1 = "select ID,PIN from assessors where ID='$AID'";
$result1=mysql_query($query1);
$num=mysql_numrows($result1);
$PIN_STATUS = "NOT_OK";
while($r=mysql_fetch_array($result1))
{
$TAID =$r["ID"];
$TPIN =$r["PIN"];
if($TAID == $AID)
{
if($TPIN == $PIN)
{
$PIN_STATUS = "OK";
}
}
}
if ($PIN_STATUS == "OK")
{
$true_array++;
$query1 = "DELETE FROM attendance WHERE ID='$ID' and Date='$Date'";
$result1=mysql_query($query1);
$query1 = "Insert into attendance(ID,UnitStandardID,Date,Time,AssessorID) VALUES ('$ID','$Booking','$Date','$Time','$AID')";
$result1=mysql_query($query1);
$s = $ID.' was booked successfully for Leave type '.$Booking.' on the following Date: '.$Date;
$in = mysql_affected_rows();
// echo $s;
?>
<table width="1000">
<TR>
<?PHP
if($in == 1)
{
?>
<TD width="60">
<img src="./images/success.jpg">
</tD>
<TD> <font size="2" face="bmwtyperegular">
<?PHP echo $s; ?>;
</tD>
</tr>
<?PHP
}
?>
<?PHP
if($in <> 1)
{
?>
<TD width="60">
<img src="./images/error.jpg">
</tD>
<TD> <font size="2" face="bmwtyperegular">
Register was not Signed!
</tD>
</tr>
<?PHP
}
?>
</table>
<?PHP
}
mysql_close();
?>
</body>
</font>
</html> |
Thanks in advance... |
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James Blond
Moderator
Joined: 19 Jan 2006
Posts: 7371
Location: Germany, Next to Hamburg
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| Posted: Mon 11 Apr '11 20:54 Post subject: |
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While inseting you should use something like this. To see if your query fails.
| Code: |
if(! mysql_query($query1)){
echo mysql_error();
}
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Do you get any error messages? It is also recommend to turn on error reporting during development
| Code: |
ini_set("display_errors",1);
error_reporting(E_ALL);
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smilerdude
Joined: 11 Apr 2011
Posts: 7
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| Posted: Tue 12 Apr '11 1:14 Post subject: |
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What's the column data type of ID ?
Are you trying to insert a string value into a column with type INT/DOUBLE/FLOAT ?
Depending on the answer, you might need to drop the single ' quotes that surround $ID in the INSERT statement.
e.g.
$query1 = "Insert into attendance(ID,UnitStandardID,Date,Time,AssessorID) VALUES ($ID,'$Booking','$Date','$Time','$AID')";
' |
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fifimtwana
Joined: 24 Feb 2011
Posts: 22
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| Posted: Tue 12 Apr '11 8:30 Post subject: PHP and Mysql |
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| The data type for the field ID is text |
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Virsacer
Joined: 16 Jan 2010
Posts: 108
Location: Germany, Darmstadt
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