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 Topic: Parse error...Error on line <LINE#>??? |
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kr33
Joined: 19 Sep 2006
Posts: 64
Location: South Africa
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 Posted: Tue 26 Sep '06 10:24 Post subject: Parse error...Error on line <LINE#>??? |
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Hi, I'm back
I've solved most of my problems, now theres another problem.
I wrote a script to query the database and display it using tables,
I am using the heredoc method for creating the rows dynamically.
My code seems fine, logically and my syntax seems fine. But it tells me that there is a parse error on line 98, but my last line of code, where i close the php section with ?> is on line 97. I don't know what could be the problem.
Any advice?
Thanks
| Quote: | | Everyman has to go through hell...to reach his paradise |
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James Blond
Moderator
Joined: 19 Jan 2006
Posts: 7371
Location: Germany, Next to Hamburg
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| Posted: Tue 26 Sep '06 10:38 Post subject: |
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Heredoc style is fine to use. It allows nice coding without lookibf for the quotes. To the Problem
| Code: |
echo <<<END
new bla;
bla->bla();
<a href="$blub">blub</a>
END;
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The last statement END; in this example must be in very beginning of a line
no space and no tab. It is very worse that PHP do not find the end if there is a space...  I hate that! On a large code with tabs for codecleanes that gettin' on my nervs! |
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kr33
Joined: 19 Sep 2006
Posts: 64
Location: South Africa
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| Posted: Tue 26 Sep '06 12:17 Post subject: |
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I will try that, thanks.
But come to think of it my code is as follows :
| Code: |
while ($row = mysql_fetch_array($query_d)) {
$movie_n = $row['movie_name'];
$movie_d = $row['movie_director'];
$movie_a = $row['movie_leadactor'];
$movie .=<<<EOD
<tr>
<td>$movie_n</td>
<td>$movie_d</td>
<td>$movie_a</td>
</tr>
EOD;
}
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My code is indented like how i've type it above, I did not code like the following:
| Code: |
while ($row = mysql_fetch_array($query_d)) {
$movie_n = $row['movie_name'];
$movie_d = $row['movie_director'];
$movie_a = $row['movie_leadactor'];
$movie .=<<<EOD
<tr>
<td>$movie_n</td>
<td>$movie_d</td>
<td>$movie_a</td>
</tr>
EOD;
}
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Which way does it or should it be? The first code snippet or the second code snippet?
Thanks |
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James Blond
Moderator
Joined: 19 Jan 2006
Posts: 7371
Location: Germany, Next to Hamburg
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| Posted: Tue 26 Sep '06 12:30 Post subject: |
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it can be like
| Code: |
while ($row = mysql_fetch_array($query_d)) {
$movie_n = $row['movie_name'];
$movie_d = $row['movie_director'];
$movie_a = $row['movie_leadactor'];
$movie .=<<<EOD
<tr>
<td>$movie_n</td>
<td>$movie_d</td>
<td>$movie_a</td>
</tr>
EOD;
//only this EOD; need to be with no space
}
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Find your own way  only make sure that you can read the code fast, even when haven't read it more than one year.
Don't copy the code from the forum. Don't kow why, but it don't work when paste post in forum & copy and paste and rty. 
Also be fast would be in-line coding
I am a bit confused! Why do you use here doc for a string? Here doc is for echo'ing. The example below would also work. Formating will be saved!
| Code: |
while ($row = mysql_fetch_array($query_d)) {
$movie_n = $row['movie_name'];
$movie_d = $row['movie_director'];
$movie_a = $row['movie_leadactor'];
$movie .="
<tr>
<td>$movie_n</td>
<td>$movie_d</td>
<td>$movie_a</td>
</tr>
";
}
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Much easier is a direct output
| Code: |
while ($row = mysql_fetch_array($query_d)) {
$movie_n = $row['movie_name'];
$movie_d = $row['movie_director'];
$movie_a = $row['movie_leadactor'];
?>
<tr>
<td><?php echo $movie_n; ?></td>
<td><?php echo $movie_d; ?></td>
<td><?php echo $movie_a; ?></td>
</tr>
<?php
}
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kr33
Joined: 19 Sep 2006
Posts: 64
Location: South Africa
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| Posted: Tue 26 Sep '06 12:38 Post subject: |
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| Thanks a million....I just hope to get php wrapped around my finger |
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